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28.26/3.14=3.14r^2/3.14
We move all terms to the left:
28.26/3.14-(3.14r^2/3.14)=0
We add all the numbers together, and all the variables
-(3.14r^2/3.14)+9=0
We get rid of parentheses
-3.14r^2/3.14+9=0
We multiply all the terms by the denominator
-3.14r^2+9*3.14=0
We add all the numbers together, and all the variables
-3.14r^2+28.26=0
a = -3.14; b = 0; c = +28.26;
Δ = b2-4ac
Δ = 02-4·(-3.14)·28.26
Δ = 354.9456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{354.9456}}{2*-3.14}=\frac{0-\sqrt{354.9456}}{-6.28} =-\frac{\sqrt{}}{-6.28} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{354.9456}}{2*-3.14}=\frac{0+\sqrt{354.9456}}{-6.28} =\frac{\sqrt{}}{-6.28} $
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